-16t^2-26t+360=0

Solution for -16t^2-26t+360=0 equation:

-16t^2-26t+360=0

a = -16; b = -26; c = +360;
Δ = b2-4ac
Δ = -262-4·(-16)·360
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23716}=154$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-154}{2*-16}=\frac{-128}{-32}
=+4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+154}{2*-16}=\frac{180}{-32}
=-5+5/8
$